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Fix kbName initialization

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Second argument of substr is the length of the substring, _not_ the position. With positions, it's better to do like this.

Example:
```sh
[2023-01-29 13:08:00.927] [debug] hyprland IPC received activelayout>>ITE Tech. Inc. ITE Device(8910) Keyboard,Russian (with Ukrainian-Belorussian layout)
[2023-01-29 13:08:00.927] [debug] kbName is ITE Tech. Inc. ITE Device(8910) Keyboard,Russian (with
```

After the fix it's correct:
```sh
[2023-01-29 13:11:11.408] [debug] hyprland IPC received activelayout>>ITE Tech. Inc. ITE Device(8910) Keyboard,Russian (with Ukrainian-Belorussian layout)
[2023-01-29 13:11:11.408] [debug] kbName is ITE Tech. Inc. ITE Device(8910) Keyboard
```
This commit is contained in:
Oleksandr Kulkov 2023-01-29 13:14:05 +01:00 committed by GitHub
parent 0ecfce9c61
commit 220b859948
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1 changed files with 1 additions and 1 deletions
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src/modules/hyprland/language.cpp
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@ -49,7 +49,7 @@ auto Language::update() -> void {
void Language::onEvent(const std::string& ev) { void Language::onEvent(const std::string& ev) {
std::lock_guard<std::mutex> lg(mutex_); std::lock_guard<std::mutex> lg(mutex_);
auto kbName = ev.substr(ev.find_last_of('>') + 1, ev.find_first_of(',')); std::string kbName(begin(ev) + ev.find_last_of('>') + 1, begin(ev) + ev.find_first_of(','));
auto layoutName = ev.substr(ev.find_first_of(',') + 1); auto layoutName = ev.substr(ev.find_first_of(',') + 1);
if (config_.isMember("keyboard-name") && kbName != config_["keyboard-name"].asString()) if (config_.isMember("keyboard-name") && kbName != config_["keyboard-name"].asString())