docker-offlineimap/offlineimap/imaputil.py
Nicolas Sebrecht b8aaf4cf43 imaputil.py: factorize the flag map
Instead of repeating a mapping table twice, once for each direction, it is only
stored once.  This is safer and faster.

As the patch stands, it makes no custom flags available.  The behaviour
is exactly as before.

Patch-written-by: Dan Christensen <jdc@uwo.ca>
Signed-off-by: Nicolas Sebrecht <nicolas.s-dev@laposte.net>
2010-12-09 19:52:48 +01:00

208 lines
7.2 KiB
Python

# IMAP utility module
# Copyright (C) 2002 John Goerzen
# <jgoerzen@complete.org>
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
import re, string, types
from offlineimap.ui import UIBase
quotere = re.compile('^("(?:[^"]|\\\\")*")')
def debug(*args):
msg = []
for arg in args:
msg.append(str(arg))
UIBase.getglobalui().debug('imap', " ".join(msg))
def dequote(string):
"""Takes a string which may or may not be quoted and returns it, unquoted.
This function does NOT consider parenthised lists to be quoted.
"""
debug("dequote() called with input:", string)
if not (string[0] == '"' and string[-1] == '"'):
return string
string = string[1:-1] # Strip off quotes.
string = string.replace('\\"', '"')
string = string.replace('\\\\', '\\')
debug("dequote() returning:", string)
return string
def flagsplit(string):
if string[0] != '(' or string[-1] != ')':
raise ValueError, "Passed string '%s' is not a flag list" % string
return imapsplit(string[1:-1])
def options2hash(list):
debug("options2hash called with input:", list)
retval = {}
counter = 0
while (counter < len(list)):
retval[list[counter]] = list[counter + 1]
counter += 2
debug("options2hash returning:", retval)
return retval
def flags2hash(string):
return options2hash(flagsplit(string))
def imapsplit(imapstring):
"""Takes a string from an IMAP conversation and returns a list containing
its components. One example string is:
(\\HasNoChildren) "." "INBOX.Sent"
The result from parsing this will be:
['(\\HasNoChildren)', '"."', '"INBOX.Sent"']"""
debug("imapsplit() called with input:", imapstring)
if type(imapstring) != types.StringType:
debug("imapsplit() got a non-string input; working around.")
# Sometimes, imaplib will throw us a tuple if the input
# contains a literal. See Python bug
# #619732 at https://sourceforge.net/tracker/index.php?func=detail&aid=619732&group_id=5470&atid=105470
# One example is:
# result[0] = '() "\\\\" Admin'
# result[1] = ('() "\\\\" {19}', 'Folder\\2')
#
# This function will effectively get result[0] or result[1], so
# if we get the result[1] version, we need to parse apart the tuple
# and figure out what to do with it. Each even-numbered
# part of it should end with the {} number, and each odd-numbered
# part should be directly a part of the result. We'll
# artificially quote it to help out.
retval = []
for i in range(len(imapstring)):
if i % 2: # Odd: quote then append.
arg = imapstring[i]
# Quote code lifted from imaplib
arg = arg.replace('\\', '\\\\')
arg = arg.replace('"', '\\"')
arg = '"%s"' % arg
debug("imapsplit() non-string [%d]: Appending %s" %\
(i, arg))
retval.append(arg)
else:
# Even -- we have a string that ends with a literal
# size specifier. We need to strip off that, then run
# what remains through the regular imapsplit parser.
# Recursion to the rescue.
arg = imapstring[i]
arg = re.sub('\{\d+\}$', '', arg)
debug("imapsplit() non-string [%d]: Feeding %s to recursion" %\
(i, arg))
retval.extend(imapsplit(arg))
debug("imapsplit() non-string: returning %s" % str(retval))
return retval
workstr = imapstring.strip()
retval = []
while len(workstr):
if workstr[0] == '(':
rparenc = 1 # count of right parenthesis to match
rpareni = 1 # position to examine
while rparenc: # Find the end of the group.
if workstr[rpareni] == ')': # end of a group
rparenc -= 1
elif workstr[rpareni] == '(': # start of a group
rparenc += 1
rpareni += 1 # Move to next character.
parenlist = workstr[0:rpareni]
workstr = workstr[rpareni:].lstrip()
retval.append(parenlist)
elif workstr[0] == '"':
quotelist = quotere.search(workstr).group(1)
workstr = workstr[len(quotelist):].lstrip()
retval.append(quotelist)
else:
splits = string.split(workstr, maxsplit = 1)
splitslen = len(splits)
# The unquoted word is splits[0]; the remainder is splits[1]
if splitslen == 2:
# There's an unquoted word, and more string follows.
retval.append(splits[0])
workstr = splits[1] # split will have already lstripped it
continue
elif splitslen == 1:
# We got a last unquoted word, but nothing else
retval.append(splits[0])
# Nothing remains. workstr would be ''
break
elif splitslen == 0:
# There was not even an unquoted word.
break
debug("imapsplit() returning:", retval)
return retval
flagmap = [('\\Seen', 'S'),
('\\Answered', 'R'),
('\\Flagged', 'F'),
('\\Deleted', 'T'),
('\\Draft', 'D')]
def flagsimap2maildir(flagstring):
retval = []
imapflaglist = [x.lower() for x in flagstring[1:-1].split()]
for imapflag, maildirflag in flagmap:
if imapflag.lower() in imapflaglist:
retval.append(maildirflag)
retval.sort()
return retval
def flagsmaildir2imap(maildirflaglist):
retval = []
for imapflag, maildirflag in flagmap:
if maildirflag in maildirflaglist:
retval.append(imapflag)
retval.sort()
return '(' + ' '.join(retval) + ')'
def listjoin(list):
start = None
end = None
retval = []
def getlist(start, end):
if start == end:
return(str(start))
else:
return(str(start) + ":" + str(end))
for item in list:
if start == None:
# First item.
start = item
end = item
elif item == end + 1:
# An addition to the list.
end = item
else:
# Here on: starting a new list.
retval.append(getlist(start, end))
start = item
end = item
if start != None:
retval.append(getlist(start, end))
return ",".join(retval)