416df0fc44
In an IMAP run where we did not have to sync anything, I spend nearly a fulls second in imaputil.debug() without even having debug output enabled. imapsplit is mainly called by flagsplit() which will also do debug output, so we get TONS of nearly duplicate debug output in the log which makes it really hard to analyze. Cut down the debug logging in imapsplit, we should be debug logging stuff at a slightly higher level than here anyway. This one-line change sped up my folder sync (without having to sync anything) by 0.5 seconds even when debugging is disabled. Signed-off-by: Sebastian Spaeth <Sebastian@SSpaeth.de> Signed-off-by: Nicolas Sebrecht <nicolas.s-dev@laposte.net>
206 lines
7.0 KiB
Python
206 lines
7.0 KiB
Python
# IMAP utility module
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# Copyright (C) 2002 John Goerzen
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# <jgoerzen@complete.org>
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#
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
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import re
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import string
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import types
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from offlineimap.ui import getglobalui
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quotere = re.compile('^("(?:[^"]|\\\\")*")')
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def debug(*args):
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msg = []
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for arg in args:
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msg.append(str(arg))
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getglobalui().debug('imap', " ".join(msg))
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def dequote(string):
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"""Takes a string which may or may not be quoted and returns it, unquoted.
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This function does NOT consider parenthised lists to be quoted.
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"""
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if not (string[0] == '"' and string[-1] == '"'):
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return string
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string = string[1:-1] # Strip off quotes.
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string = string.replace('\\"', '"')
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string = string.replace('\\\\', '\\')
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debug("dequote() returning:", string)
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return string
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def flagsplit(string):
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if string[0] != '(' or string[-1] != ')':
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raise ValueError, "Passed string '%s' is not a flag list" % string
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return imapsplit(string[1:-1])
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def options2hash(list):
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retval = {}
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counter = 0
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while (counter < len(list)):
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retval[list[counter]] = list[counter + 1]
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counter += 2
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debug("options2hash returning:", retval)
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return retval
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def flags2hash(string):
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return options2hash(flagsplit(string))
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def imapsplit(imapstring):
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"""Takes a string from an IMAP conversation and returns a list containing
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its components. One example string is:
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(\\HasNoChildren) "." "INBOX.Sent"
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The result from parsing this will be:
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['(\\HasNoChildren)', '"."', '"INBOX.Sent"']"""
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if type(imapstring) != types.StringType:
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debug("imapsplit() got a non-string input; working around.")
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# Sometimes, imaplib will throw us a tuple if the input
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# contains a literal. See Python bug
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# #619732 at https://sourceforge.net/tracker/index.php?func=detail&aid=619732&group_id=5470&atid=105470
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# One example is:
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# result[0] = '() "\\\\" Admin'
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# result[1] = ('() "\\\\" {19}', 'Folder\\2')
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#
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# This function will effectively get result[0] or result[1], so
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# if we get the result[1] version, we need to parse apart the tuple
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# and figure out what to do with it. Each even-numbered
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# part of it should end with the {} number, and each odd-numbered
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# part should be directly a part of the result. We'll
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# artificially quote it to help out.
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retval = []
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for i in range(len(imapstring)):
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if i % 2: # Odd: quote then append.
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arg = imapstring[i]
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# Quote code lifted from imaplib
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arg = arg.replace('\\', '\\\\')
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arg = arg.replace('"', '\\"')
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arg = '"%s"' % arg
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debug("imapsplit() non-string [%d]: Appending %s" %\
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(i, arg))
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retval.append(arg)
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else:
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# Even -- we have a string that ends with a literal
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# size specifier. We need to strip off that, then run
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# what remains through the regular imapsplit parser.
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# Recursion to the rescue.
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arg = imapstring[i]
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arg = re.sub('\{\d+\}$', '', arg)
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debug("imapsplit() non-string [%d]: Feeding %s to recursion" %\
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(i, arg))
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retval.extend(imapsplit(arg))
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debug("imapsplit() non-string: returning %s" % str(retval))
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return retval
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workstr = imapstring.strip()
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retval = []
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while len(workstr):
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if workstr[0] == '(':
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rparenc = 1 # count of right parenthesis to match
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rpareni = 1 # position to examine
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while rparenc: # Find the end of the group.
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if workstr[rpareni] == ')': # end of a group
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rparenc -= 1
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elif workstr[rpareni] == '(': # start of a group
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rparenc += 1
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rpareni += 1 # Move to next character.
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parenlist = workstr[0:rpareni]
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workstr = workstr[rpareni:].lstrip()
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retval.append(parenlist)
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elif workstr[0] == '"':
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quotelist = quotere.search(workstr).group(1)
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workstr = workstr[len(quotelist):].lstrip()
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retval.append(quotelist)
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else:
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splits = string.split(workstr, maxsplit = 1)
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splitslen = len(splits)
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# The unquoted word is splits[0]; the remainder is splits[1]
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if splitslen == 2:
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# There's an unquoted word, and more string follows.
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retval.append(splits[0])
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workstr = splits[1] # split will have already lstripped it
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continue
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elif splitslen == 1:
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# We got a last unquoted word, but nothing else
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retval.append(splits[0])
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# Nothing remains. workstr would be ''
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break
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elif splitslen == 0:
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# There was not even an unquoted word.
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break
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return retval
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flagmap = [('\\Seen', 'S'),
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('\\Answered', 'R'),
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('\\Flagged', 'F'),
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('\\Deleted', 'T'),
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('\\Draft', 'D')]
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def flagsimap2maildir(flagstring):
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retval = []
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imapflaglist = [x.lower() for x in flagstring[1:-1].split()]
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for imapflag, maildirflag in flagmap:
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if imapflag.lower() in imapflaglist:
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retval.append(maildirflag)
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retval.sort()
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return retval
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def flagsmaildir2imap(maildirflaglist):
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retval = []
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for imapflag, maildirflag in flagmap:
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if maildirflag in maildirflaglist:
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retval.append(imapflag)
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retval.sort()
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return '(' + ' '.join(retval) + ')'
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def listjoin(list):
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start = None
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end = None
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retval = []
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def getlist(start, end):
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if start == end:
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return(str(start))
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else:
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return(str(start) + ":" + str(end))
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for item in list:
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if start == None:
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# First item.
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start = item
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end = item
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elif item == end + 1:
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# An addition to the list.
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end = item
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else:
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# Here on: starting a new list.
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retval.append(getlist(start, end))
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start = item
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end = item
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if start != None:
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retval.append(getlist(start, end))
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return ",".join(retval)
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