0e4afa9132
When synclabels config flag is set to "yes" for the GMail repo, offlineimap fetches the message labels along with the messages, and embeds them into the body under the header X-Keywords (or whatever 'labelsheader' was set to), as a comma separated list. It also adds an extra pass to savemessageto, that performs label synchronization on existing messages from GMail to local, the same way it is done with flags. We also introduce GmailMaildir repository that adds functionality to change message labels. It keeps track of messages modification time, so one can quickly detect when the labels may have changed. Signed-off-by: Eygene Ryabinkin <rea@codelabs.ru>
263 lines
9.3 KiB
Python
263 lines
9.3 KiB
Python
# IMAP utility module
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# Copyright (C) 2002 John Goerzen
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# <jgoerzen@complete.org>
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#
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
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import re
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import string
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from offlineimap.ui import getglobalui
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def __debug(*args):
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msg = []
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for arg in args:
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msg.append(str(arg))
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getglobalui().debug('imap', " ".join(msg))
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def dequote(string):
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"""Takes string which may or may not be quoted and unquotes it.
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It only considers double quotes. This function does NOT consider
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parenthised lists to be quoted.
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"""
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if string and string.startswith('"') and string.endswith('"'):
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string = string[1:-1] # Strip off the surrounding quotes.
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string = string.replace('\\"', '"')
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string = string.replace('\\\\', '\\')
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return string
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def quote(string):
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"""Takes an unquoted string and quotes it.
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It only adds double quotes. This function does NOT consider
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parenthised lists to be quoted.
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"""
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string = string.replace('"', '\\"')
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string = string.replace('\\', '\\\\')
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return '"%s"' % string
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def flagsplit(string):
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"""Converts a string of IMAP flags to a list
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:returns: E.g. '(\\Draft \\Deleted)' returns ['\\Draft','\\Deleted'].
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(FLAGS (\\Seen Old) UID 4807) returns
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['FLAGS,'(\\Seen Old)','UID', '4807']
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"""
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if string[0] != '(' or string[-1] != ')':
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raise ValueError("Passed string '%s' is not a flag list" % string)
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return imapsplit(string[1:-1])
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def __options2hash(list):
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"""convert list [1,2,3,4,5,6] to {1:2, 3:4, 5:6}"""
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# effectively this does dict(zip(l[::2],l[1::2])), however
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# measurements seemed to have indicated that the manual variant is
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# faster for mosly small lists.
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retval = {}
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counter = 0
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while (counter < len(list)):
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retval[list[counter]] = list[counter + 1]
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counter += 2
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__debug("__options2hash returning:", retval)
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return retval
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def flags2hash(flags):
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"""Converts IMAP response string from eg IMAP4.fetch() to a hash.
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E.g. '(FLAGS (\\Seen Old) UID 4807)' leads to
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{'FLAGS': '(\\Seen Old)', 'UID': '4807'}"""
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return __options2hash(flagsplit(flags))
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def imapsplit(imapstring):
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"""Takes a string from an IMAP conversation and returns a list containing
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its components. One example string is:
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(\\HasNoChildren) "." "INBOX.Sent"
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The result from parsing this will be:
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['(\\HasNoChildren)', '"."', '"INBOX.Sent"']"""
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if not isinstance(imapstring, basestring):
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__debug("imapsplit() got a non-string input; working around.")
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# Sometimes, imaplib will throw us a tuple if the input
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# contains a literal. See Python bug
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# #619732 at https://sourceforge.net/tracker/index.php?func=detail&aid=619732&group_id=5470&atid=105470
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# One example is:
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# result[0] = '() "\\\\" Admin'
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# result[1] = ('() "\\\\" {19}', 'Folder\\2')
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#
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# This function will effectively get result[0] or result[1], so
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# if we get the result[1] version, we need to parse apart the tuple
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# and figure out what to do with it. Each even-numbered
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# part of it should end with the {} number, and each odd-numbered
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# part should be directly a part of the result. We'll
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# artificially quote it to help out.
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retval = []
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for i in range(len(imapstring)):
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if i % 2: # Odd: quote then append.
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arg = imapstring[i]
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# Quote code lifted from imaplib
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arg = arg.replace('\\', '\\\\')
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arg = arg.replace('"', '\\"')
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arg = '"%s"' % arg
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__debug("imapsplit() non-string [%d]: Appending %s" %\
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(i, arg))
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retval.append(arg)
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else:
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# Even -- we have a string that ends with a literal
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# size specifier. We need to strip off that, then run
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# what remains through the regular imapsplit parser.
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# Recursion to the rescue.
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arg = imapstring[i]
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arg = re.sub('\{\d+\}$', '', arg)
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__debug("imapsplit() non-string [%d]: Feeding %s to recursion" %\
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(i, arg))
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retval.extend(imapsplit(arg))
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__debug("imapsplit() non-string: returning %s" % str(retval))
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return retval
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workstr = imapstring.strip()
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retval = []
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while len(workstr):
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# handle parenthized fragments (...()...)
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if workstr[0] == '(':
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rparenc = 1 # count of right parenthesis to match
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rpareni = 1 # position to examine
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while rparenc: # Find the end of the group.
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if workstr[rpareni] == ')': # end of a group
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rparenc -= 1
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elif workstr[rpareni] == '(': # start of a group
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rparenc += 1
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rpareni += 1 # Move to next character.
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parenlist = workstr[0:rpareni]
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workstr = workstr[rpareni:].lstrip()
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retval.append(parenlist)
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elif workstr[0] == '"':
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# quoted fragments '"...\"..."'
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(quoted, rest) = __split_quoted(workstr)
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retval.append(quoted)
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workstr = rest
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else:
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splits = string.split(workstr, maxsplit = 1)
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splitslen = len(splits)
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# The unquoted word is splits[0]; the remainder is splits[1]
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if splitslen == 2:
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# There's an unquoted word, and more string follows.
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retval.append(splits[0])
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workstr = splits[1] # split will have already lstripped it
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continue
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elif splitslen == 1:
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# We got a last unquoted word, but nothing else
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retval.append(splits[0])
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# Nothing remains. workstr would be ''
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break
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elif splitslen == 0:
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# There was not even an unquoted word.
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break
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return retval
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flagmap = [('\\Seen', 'S'),
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('\\Answered', 'R'),
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('\\Flagged', 'F'),
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('\\Deleted', 'T'),
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('\\Draft', 'D')]
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def flagsimap2maildir(flagstring):
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"""Convert string '(\\Draft \\Deleted)' into a flags set(DR)"""
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retval = set()
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imapflaglist = flagstring[1:-1].split()
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for imapflag, maildirflag in flagmap:
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if imapflag in imapflaglist:
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retval.add(maildirflag)
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return retval
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def flagsmaildir2imap(maildirflaglist):
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"""Convert set of flags ([DR]) into a string '(\\Deleted \\Draft)'"""
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retval = []
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for imapflag, maildirflag in flagmap:
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if maildirflag in maildirflaglist:
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retval.append(imapflag)
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return '(' + ' '.join(sorted(retval)) + ')'
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def uid_sequence(uidlist):
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"""Collapse UID lists into shorter sequence sets
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[1,2,3,4,5,10,12,13] will return "1:5,10,12:13". This function sorts
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the list, and only collapses if subsequent entries form a range.
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:returns: The collapsed UID list as string"""
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def getrange(start, end):
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if start == end:
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return(str(start))
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return "%s:%s" % (start, end)
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if not len(uidlist): return '' # Empty list, return
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start, end = None, None
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retval = []
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# Force items to be longs and sort them
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sorted_uids = sorted(map(int, uidlist))
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for item in iter(sorted_uids):
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item = int(item)
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if start == None: # First item
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start, end = item, item
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elif item == end + 1: # Next item in a range
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end = item
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else: # Starting a new range
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retval.append(getrange(start, end))
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start, end = item, item
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retval.append(getrange(start, end)) # Add final range/item
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return ",".join(retval)
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def __split_quoted(string):
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"""
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Looks for the ending quote character in the string that starts
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with quote character, splitting out quoted component and the
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rest of the string (without possible space between these two
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parts.
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First character of the string is taken to be quote character.
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Examples:
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- "this is \" a test" (\\None) => ("this is \" a test", (\\None))
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- "\\" => ("\\", )
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"""
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if len(string) == 0:
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return ('', '')
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q = quoted = string[0]
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rest = string[1:]
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while True:
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next_q = rest.find(q)
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if next_q == -1:
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raise ValueError("can't find ending quote '%s' in '%s'" % (q, string))
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# If quote is preceeded by even number of backslashes,
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# then it is the ending quote, otherwise the quote
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# character is escaped by backslash, so we should
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# continue our search.
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is_escaped = False
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i = next_q - 1
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while i >= 0 and rest[i] == '\\':
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i -= 1
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is_escaped = not is_escaped
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quoted += rest[0:next_q + 1]
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rest = rest[next_q + 1:]
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if not is_escaped:
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return (quoted, rest.lstrip())
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