Rename addmessageheader()'s crlf parameter to linebreak
The parameter's value is a string representing the linebreak, and can sometimes contain just '\n', in which case naming it crlf is slightly misleading. Signed-off-by: Eygene Ryabinkin <rea@codelabs.ru>
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@ -420,13 +420,13 @@ next line\n
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"""
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def addmessageheader(self, content, crlf, headername, headervalue):
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def addmessageheader(self, content, linebreak, headername, headervalue):
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"""
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Adds new header to the provided message.
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Arguments:
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- content: message content, headers and body as a single string
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- crlf: string that carries line ending
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- linebreak: string that carries line ending
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- headername: name of the header to add
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- headervalue: value of the header to add
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@ -434,12 +434,12 @@ next line\n
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self.ui.debug('',
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'addmessageheader: called to add %s: %s' % (headername,
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headervalue))
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prefix = crlf
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prefix = linebreak
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suffix = ''
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insertionpoint = content.find(crlf + crlf)
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insertionpoint = content.find(linebreak * 2)
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if insertionpoint == 0 or insertionpoint == -1:
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prefix = ''
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suffix = crlf
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suffix = linebreak
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if insertionpoint == -1:
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insertionpoint = 0
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# When body starts immediately, without preceding '\n'
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@ -447,8 +447,8 @@ next line\n
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# we seen many broken ones), we should add '\n' to make
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# new (and the only header, in this case) to be properly
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# separated from the message body.
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if content[0:len(crlf)] != crlf:
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suffix = suffix + crlf
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if content[0:len(linebreak)] != linebreak:
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suffix = suffix + linebreak
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self.ui.debug('', 'addmessageheader: insertionpoint = %d' % insertionpoint)
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headers = content[0:insertionpoint]
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