repository.LocalStatus: Remove code duplication
Make getfolders() invoke getfolder() for each folder rather than duplicating code. Also add a forgetfolders() implementation. Signed-off-by: Sebastian Spaeth <Sebastian@SSpaeth.de> Signed-off-by: Nicolas Sebrecht <nicolas.s-dev@laposte.net>
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@ -48,24 +48,28 @@ class LocalStatusRepository(BaseRepository):
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os.fsync(file.fileno())
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os.fsync(file.fileno())
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file.close()
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file.close()
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os.rename(filename + ".tmp", filename)
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os.rename(filename + ".tmp", filename)
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# Invalidate the cache.
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# Invalidate the cache.
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self.folders = None
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self.folders = None
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def getfolders(self):
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retval = []
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for folder in os.listdir(self.directory):
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retval.append(folder.LocalStatus.LocalStatusFolder(self.directory,
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folder, self, self.accountname,
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self.config))
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return retval
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def getfolder(self, foldername):
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def getfolder(self, foldername):
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return folder.LocalStatus.LocalStatusFolder(self.directory, foldername,
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"""Return the Folder() object for a foldername"""
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self, self.accountname,
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return self.LocalStatusFolderClass(self.directory, foldername,
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self.config)
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self, self.accountname,
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self.config)
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def getfolders(self):
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"""Returns a list of ALL folders on this server.
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This is currently nowhere used in the code."""
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if self._folders != None:
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return self._folders
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for folder in os.listdir(self.directory):
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self._folders = retval.append(self.getfolder(folder))
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return self._folders
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def forgetfolders(self):
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"""Forgets the cached list of folders, if any. Useful to run
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after a sync run."""
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self._folders = None
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